An object having a velocity 5 m/s is accelerated at the rate 2 m/s2 for 6 s. Find the distance travelled during the period of acceleration

Question

An object having a velocity 5 m/s is accelerated at the rate 2 m/s2 for 6 s. Find the distance travelled during the period of acceleration (A) 60 m (B) 25 m (C) 36 m (D) 66 m

Tardigrade Admin · Accepted Answer

Given, u=5 m / s , a=+2 ms -2 and t=6 s Equation of motion S=u t+(1/2) a t2 So, by putting the values, we get S =5 × 6+(1/2) × 2 × 62 =30+36=66 m

Q. An object having a velocity $5 m / s$ is accelerated at the rate $2 m / s^{2}$ for $6 s .$ Find the distance travelled during the period of acceleration

60 m

25 m

36 m

66 m

45 m

Given, $u = 5 m / s, a = + 2 m s^{- 2}$ and $t = 6 s$
Equation of motion
$S = u t + \frac{1}{2} a t^{2}$
So, by putting the values, we get
$S = 5 \times 6 + \frac{1}{2} \times 2 \times 6^{2}$
$= 30 + 36 = 66 m$

Q. An object having a velocity 5m/s is accelerated at the rate 2m/s2 for 6s. Find the distance travelled during the period of acceleration