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Q.
An object having a velocity $5\, m/s$ is accelerated at the rate $2 \; m/s^2$ for $6\, s.$ Find the distance travelled during the period of acceleration
Given, $u=5 m / s , a=+2 ms ^{-2}$ and $t=6 s$
Equation of motion
$S=u t+\frac{1}{2} a t^{2}$
So, by putting the values, we get
$S =5 \times 6+\frac{1}{2} \times 2 \times 6^{2} $
$=30+36=66\,m$