An object falling through a fluid is observed to have acceleration given by a = g - bv where g = gravitational acceleration and b is constant. After a long time of release, it is observed to fall with constant speed. The value of constant speed is

Question

An object falling through a fluid is observed to have acceleration given by a = g - bv where g = gravitational acceleration and b is constant. After a long time of release, it is observed to fall with constant speed. The value of constant speed is (A) (g/b) (B) (b/g) (C) bg (D) b

Tardigrade Admin · Accepted Answer

Here, a= g - bv When an object falls with constant speed vc, its acceleration becomes zero. ∴ g-bvc=0 or vc=(g/b)

Q. An object falling through a fluid is observed to have acceleration given by $a = g - b v$ where $g =$ gravitational acceleration and $b$ is constant. After a long time of release, it is observed to fall with constant speed. The value of constant speed is

$\frac{g}{b}$

$\frac{b}{g}$

$b g$

$b$

Here, $a = g - b v$
When an object falls with constant speed $v_{c}$ , its acceleration becomes zero.
$∴ g - b v_{c} = 0$ or $v_{c} = \frac{g}{b}$

Q. An object falling through a fluid is observed to have acceleration given by a=g−bv where g= gravitational acceleration and b is constant. After a long time of release, it is observed to fall with constant speed. The value of constant speed is

bg​

gb​

bg

b

Here, a=g−bv When an object falls with constant speed vc​, its acceleration becomes zero. ∴g−bvc​=0 or vc​=bg​

Q. An object falling through a fluid is observed to have acceleration given by $a = g - b v$ where $g =$ gravitational acceleration and $b$ is constant. After a long time of release, it is observed to fall with constant speed. The value of constant speed is

$\frac{g}{b}$

$\frac{b}{g}$

$b g$

$b$

Here, $a = g - b v$
When an object falls with constant speed $v_{c}$ , its acceleration becomes zero.
$∴ g - b v_{c} = 0$ or $v_{c} = \frac{g}{b}$