An object and a concave mirror are approaching each other with velocities 10 m/s and 5 m/s as shown in figure. The velocity of image of object at the instant shown in figure is

Question

An object and a concave mirror are approaching each other with velocities 10 m/s and 5 m/s as shown in figure. The velocity of image of object at the instant shown in figure is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-iqu1zuau4ucb.png" /> (A) 65 m/s hati (B) 65 m/s (- hati) (C) 40 m/s hati (D) 40 m/s (- hati)

Tardigrade Admin · Accepted Answer

The formula for velocity of image is given by: =VI m=(f/f - u)=(- 10/- 10 + 15)=-2 ∴ VI m=-4 VO m Therefore, vecVI-5(- hati)=-4 10 hati+5 hati ⇒ overset arrow VI=-65 hati

Q. An object and a concave mirror are approaching each other with velocities $10 m / s$ and $5 m / s$ as shown in figure. The velocity of image of object at the instant shown in figure is

$65 m / s$ $\hat{i}$

$65 m / s$ $(- \hat{i})$

$40 m / s$ $\hat{i}$

$40 m / s$ $(- \hat{i})$

The formula for velocity of image is given by :
$= V_{I m} = \frac{f}{f - u} = \frac{- 10}{- 10 + 15} = - 2$
$∴ V_{I m} = - 4 V_{O m}$
Therefore, $V_{I} - 5 (- \hat{i}) = - 4 {10 \hat{i} + 5 \hat{i}}$
$\Rightarrow V \to_{I} = - 65 \hat{i}$

Q. An object and a concave mirror are approaching each other with velocities 10m/s and 5m/s as shown in figure. The velocity of image of object at the instant shown in figure is

65m/s i^

65m/s (−i^)

40m/s i^

40m/s (−i^)