An object and a concave mirror are approaching each other with velocities 10 m/s and 5 m/s as shown in figure. The velocity of image of object at the instant shown in figure is

Question

An object and a concave mirror are approaching each other with velocities 10 m/s and 5 m/s as shown in figure. The velocity of image of object at the instant shown in figure is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-rzogxrwbxvlrkfmk.jpg" /> (A) 65 m/s hati (B) 65 m/s- hati (C) 40 m/s hati (D) 40 m/s- hati

Tardigrade Admin · Accepted Answer

The formula for velocity of image is given by: =VI m=(f/f-u)=(-10/-10+15)=-2 ∴ V Im =-4 V Om Therefore, vecV I -5- hat1=-410 hat1+5 hat1 ⇒ vecVI=-65 hat imath

Q. An object and a concave mirror are approaching each other with velocities $10 m / s$ and $5 m / s$ as shown in figure. The velocity of image of object at the instant shown in figure is

$65 m / s \hat{i}$

$65 m / s - \hat{i}$

$40 m / s \hat{i}$

$40 m / s - \hat{i}$

The formula for velocity of image is given by:
$= V_{I m} = \frac{f}{f - u} = \frac{- 10}{- 10 + 15} = - 2$
$∴ V_{I m} = - 4 V_{O m}$
Therefore, $V_{I} - 5 - \hat{1} = - 410 \hat{1} + 5 \hat{1}$
$\Rightarrow V_{I} = - 65 \overset{}{^}$

Q. An object and a concave mirror are approaching each other with velocities 10m/s and 5m/s as shown in figure. The velocity of image of object at the instant shown in figure is

65m/si^

65m/s−i^

40m/si^

40m/s−i^