An n.p.n transistor with current gain β=100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be

Question

An n.p.n transistor with current gain β=100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be (A) 0.1 V (B) 1.0 V (C) 10 V (D) 100 V

Tardigrade Admin · Accepted Answer

(v text out / v text in )=β ( R text out / R text in ) v text out =(100 × 10 × 103/103) × 10-3 =1 V

Q. An n.p.n transistor with current gain $β = 100$ in common emitter configuration is shown in figure. The output voltage of the amplifier will be

$0.1 V$

$1.0 V$

$10 V$

$100 V$

$\frac{v _{out}}{v _{in}} = β \frac{R _{out}}{R _{in}}$
$v_{out} = \frac{100 \times 10 \times 1 0 ^{3}}{1 0 ^{3}} \times 1 0^{- 3}$
$= 1 V$

Q. An n.p.n transistor with current gain β=100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be

0.1V

1.0V

10V

100V