An LED is constructed from a p-n junction diode using GaAsP. The energy gap is 1.9 eV. The wavelength of the light emitted will be equal to :

Question

An LED is constructed from a p-n junction diode using GaAsP. The energy gap is 1.9 eV. The wavelength of the light emitted will be equal to : (A) 10.4 × 10-26 m (B) 654 nm (C) 654 mathringA (D) 654 10-11 m

Tardigrade Admin · Accepted Answer

λ = (1240nm/1.9) = 652.6 nm ≃ 654 nm

Q. An $L E D$ is constructed from a $p - n$ junction diode using $G a A s P$ . The energy gap is $1.9 e V$ . The wavelength of the light emitted will be equal to :

$10.4 \times 1 0^{- 26} m$

$654 nm$

$654 \overset{˚}{A}$

$6541 0^{- 11} m$

$λ = \frac{1240 nm}{1.9} = 652.6 nm ≃ 654 nm$

Q. An LED is constructed from a p−n junction diode using GaAsP. The energy gap is 1.9eV. The wavelength of the light emitted will be equal to :

10.4×10−26m

654nm

654A˚

65410−11m