An LCR circuit has L = 10 mH, R = 3Ω , and C = 1 μ F connected in series to a source of 15 cos ω t volt . The current amplitude at a frequency that is 10% lower than the resonant frequency is

Question

An LCR circuit has L = 10 mH, R = 3Ω , and C = 1 μ F connected in series to a source of 15 cos ω t volt . The current amplitude at a frequency that is 10% lower than the resonant frequency is (A) 0.5 A (B) 0.7 A (C) 0.9 A (D) 1.1 A

Tardigrade Admin · Accepted Answer

cv=(90/100)cv0=(90/100)x(1/√LC)=9000 rad/s i0=(E0/√R2(ω L-(1)ω C)2)

Q. An LCR circuit has L = 10 mH, $R = 3Ω$ , and $C = 1 μ F$ connected in series to a source of $15 cos ω t$ volt . The current amplitude at a frequency that is 10% lower than the resonant frequency is

0.5 A

0.7 A

0.9 A

1.1 A

$c_{v} = \frac{90}{100} c_{v_{0}} = \frac{90}{100} x \frac{1}{L C} = 9000 r a d / s$
$i_{0} = \frac{E _{0}}{R ^{2} ( ω L - \frac{1}{ω C} ) ^{2}}$

Q. An LCR circuit has L = 10 mH, R=3Ω , and C=1μF connected in series to a source of 15cosωt volt . The current amplitude at a frequency that is 10% lower than the resonant frequency is