An LC circuit contains inductance L=1 μ H and capacitance C=0.01 μ F. The wavelength of electromagnetic wave generated is nearly

Question

An LC circuit contains inductance L=1 μ H and capacitance C=0.01 μ F. The wavelength of electromagnetic wave generated is nearly (A) 0.5 m (B) 5 m (C) 188 m (D) 30 m

Tardigrade Admin · Accepted Answer

v=(1/2 π √L C) λ=(c/v)=c ⋅ 2 π √L C =3 × 108 × 2 π √1 × 10-6 × 0.01 × 10-6 =3 × 108 × 2 × 3.14 × 10-7 =188.4 m

Q. An LC circuit contains inductance $L = 1 μ H$ and capacitance $C = 0.01 μ F$ . The wavelength of electromagnetic wave generated is nearly

0.5 m

5 m

188 m

30 m

$v = \frac{1}{2 π L C}$
$λ = \frac{c}{v} = c \cdot 2 π L C$
$= 3 \times 1 0^{8} \times 2 π 1 \times 1 0^{- 6} \times 0.01 \times 1 0^{- 6}$
$= 3 \times 1 0^{8} \times 2 \times 3.14 \times 1 0^{- 7}$
$= 188.4 m$

Q. An LC circuit contains inductance L=1μH and capacitance C=0.01μF. The wavelength of electromagnetic wave generated is nearly

0.5 m

5 m

188 m

30 m

v=2πLC​1​ λ=vc​=c⋅2πLC​ =3×108×2π1×10−6×0.01×10−6​ =3×108×2×3.14×10−7 =188.4m

Q. An LC circuit contains inductance $L = 1 μ H$ and capacitance $C = 0.01 μ F$ . The wavelength of electromagnetic wave generated is nearly

$v = \frac{1}{2 π L C}$
$λ = \frac{c}{v} = c \cdot 2 π L C$
$= 3 \times 1 0^{8} \times 2 π 1 \times 1 0^{- 6} \times 0.01 \times 1 0^{- 6}$
$= 3 \times 1 0^{8} \times 2 \times 3.14 \times 1 0^{- 7}$
$= 188.4 m$