An isomer of C6H14 forms three monochloro derivatives. The isomer may be - (Excluding stereo isomer)

Question

An isomer of C6H14 forms three monochloro derivatives. The isomer may be - (Excluding stereo isomer) (A) neo-pentane (B) n-hexane (C) 2, 3-dimethylbutane (D) iso-hexane

Tardigrade Admin · Accepted Answer

In n-hexane, there is a symmetry of the structure at third and fourth carbon. So, chlorine can attach to first, second, and third carbon to give 3 monochloro derivatives. These monochloro derivatives are:

Solution

Q. An isomer of C6​H14​ forms three monochloro derivatives. The isomer may be - (Excluding stereo isomer)

neo-pentane

n-hexane

2, 3-dimethylbutane

iso-hexane

In n-hexane, there is a symmetry of the structure at third and fourth carbon. So, chlorine can attach to first, second, and third carbon to give 3 monochloro derivatives. These monochloro derivatives are:

Q. An isomer of $C_{6} H_{14}$ forms three monochloro derivatives. The isomer may be -

(Excluding stereo isomer)