An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m-1. The permeability of the material of the rod is: (μo = 4π × 10-7 T m A-1)

Question

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m-1. The permeability of the material of the rod is: (μo = 4π × 10-7 T m A-1) (A) 2.4 π × 10-4 T m A-1 (B) 8.0 π × 10-5 T m A-1 (C) 2.4 π × 10-5 T m A-1 (D) 2.4 π × 10-7 T m A-1

Tardigrade Admin · Accepted Answer

Given, chim=599 Also, μr=1+ chim=600 We know, μ=μrμo μ=600×4π×10-7 μ=2400π×10-7 μ=2.4π×10-4 T m A-1

Q. An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A $m^{- 1}$ . The permeability of the material of the rod is :
$(μ_{o} = 4 π \times 1 0^{- 7} T m A^{- 1})$

$2.4 π \times 1 0^{- 4} T m A^{- 1}$

$8.0 π \times 1 0^{- 5} T m A^{- 1}$

$2.4 π \times 1 0^{- 5} T m A^{- 1}$

$2.4 π \times 1 0^{- 7} T m A^{- 1}$

Given, $χ_{m} = 599$
Also, $μ_{r} = 1 + χ_{m} = 600$
We know, $μ = μ_{r} μ_{o}$
$μ = 600 \times 4 π \times 1 0^{- 7}$
$μ = 2400 π \times 1 0^{- 7}$
$μ = 2.4 π \times 1 0^{- 4} T m A^{- 1}$

Q. An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m−1. The permeability of the material of the rod is : (μo​=4π×10−7TmA−1)

2.4π×10−4TmA−1

8.0π×10−5TmA−1

2.4π×10−5TmA−1

2.4π×10−7TmA−1