Q.
An installation consisting of an electric motor driving a water pump left 75L of water per second to a height of 4.7m . If the motor consumes a power of 5kW , then the efficiency of the installation is
Power consumed by the motor = 5kW =5×103W =5000W
Power used in lifting the water =tmgh =75×9.8×4.7 =3454.5kW
Efficiency =PowerconsumedPowerused×100% =50003454.5×100=69%