An infinitely long wire carrying current I is along Y axis such that its one end is at point A(0, b) while the wire extends upto + ∞ . The magnitude of magnetic field strength at point (a, 0).

Question

An infinitely long wire carrying current I is along Y axis such that its one end is at point A(0, b) while the wire extends upto + ∞ . The magnitude of magnetic field strength at point (a, 0). <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-buou2jhtozltqnfa.jpg" /> (A) (μ0 I/4 π a)(1+(b/√a2+b2)) (B) (μ0 I/4 π a)(1-(b/√a2+b2)) (C) (μ0 I/4 π a)(1-(a/√a2+b2)) (D) None of these

Tardigrade Admin · Accepted Answer

B=(μ0 I/4 π) (i/a)[ sin 90°+ sin (-θ)]=(μ0/4 π) (i/a)(1- sin θ) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-buou2jhtozltinxx.jpg" /> =(μ0 i/4 πa)(1-(b/√a2+b2))

Q. An infinitely long wire carrying current $I$ is along $Y$ axis such that its one end is at point $A (0, b)$ while the wire extends upto $+ \infty$ . The magnitude of magnetic field strength at point $(a, 0)$ .

$\frac{μ _{0} I}{4 πa} (1 + \frac{b}{a ^{2} + b ^{2}})$

$\frac{μ _{0} I}{4 πa} (1 - \frac{b}{a ^{2} + b ^{2}})$

$\frac{μ _{0} I}{4 πa} (1 - \frac{a}{a ^{2} + b ^{2}})$

None of these

$B = \frac{μ _{0} I}{4 π} \frac{i}{a} [sin 9 0^{\circ} + sin (- θ)] = \frac{μ _{0}}{4 π} \frac{i}{a} (1 - sin θ)$

$= \frac{μ _{0} i}{4 π ^{a}} (1 - \frac{b}{a ^{2} + b ^{2}})$

Q. An infinitely long wire carrying current I is along Y axis such that its one end is at point A(0,b) while the wire extends upto +∞ . The magnitude of magnetic field strength at point (a,0).

4πaμ0​I​(1+a2+b2​b​)

4πaμ0​I​(1−a2+b2​b​)

4πaμ0​I​(1−a2+b2​a​)