An infinite conducting sheet has surface charge density σ. The distance between two equipotential surfaces is r. The potential difference between these two surfaces is

Question

An infinite conducting sheet has surface charge density σ. The distance between two equipotential surfaces is r. The potential difference between these two surfaces is (A) (σ r/2 ε0) (B) (σ r/ε0) (C) (σ/ε0 r) (D) (σ/2 ε0 r)

Tardigrade Admin · Accepted Answer

Δ V=E d=(σ r/ε0) Δ V=(σ r/ε0)

Q. An infinite conducting sheet has surface charge density $σ$ . The distance between two equipotential surfaces is $r$ . The potential difference between these two surfaces is

$\frac{σ r}{2 ε _{0}}$

$\frac{σ r}{ε _{0}}$

$\frac{σ}{ε _{0} r}$

$\frac{σ}{2 ε _{0} r}$

$Δ V = E d = \frac{σ r}{ε _{0}}$
$Δ V = \frac{σ r}{ε _{0}}$

Q. An infinite conducting sheet has surface charge density σ. The distance between two equipotential surfaces is r. The potential difference between these two surfaces is

2ε0​σr​

ε0​σr​

ε0​rσ​

2ε0​rσ​