An infinite conducting sheet has surface charge density σ . The distance between two points is r . The potential difference (VA - VB) between these points is

Question

An infinite conducting sheet has surface charge density σ . The distance between two points is r . The potential difference (VA - VB) between these points is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hnkmx29ztt04.png" /> (A) (σ r/2 ϵ 0) (B) (σ r/ϵ 0) (C) (σ /ϵ 0 r) (D) (σ /2 ϵ 0 r)

Tardigrade Admin · Accepted Answer

VA-VB= displaystyle ∫ ab E . d r=E (b - a)=(σ r/2 (ϵ )0)

Q. An infinite conducting sheet has surface charge density $σ$ . The distance between two points is $r$ . The potential difference $(V_{A} - V_{B})$ between these points is

$\frac{σ r}{2 ϵ _{0}}$

$\frac{σ r}{ϵ _{0}}$

$\frac{σ}{ϵ _{0} r}$

$\frac{σ}{2 ϵ _{0} r}$

$V_{A} - V_{B} = \int_{a}^{b} E . d r = E (b - a) = \frac{σ r}{2 ( ϵ ) _{0}}$

Q. An infinite conducting sheet has surface charge density σ . The distance between two points is r . The potential difference (VA​−VB​) between these points is

2ϵ0​σr​

ϵ0​σr​

ϵ0​rσ​

2ϵ0​rσ​