An inductor, a capacitor and a resistor are connected in series to an AC supply. When measured with an AC voltmeter, the potential difference across the inductor, capacitor and resistor are respectively 90 V , 60 V and 40 V. Then the supply voltage is

Question

An inductor, a capacitor and a resistor are connected in series to an AC supply. When measured with an AC voltmeter, the potential difference across the inductor, capacitor and resistor are respectively 90 V , 60 V and 40 V. Then the supply voltage is (A) 190 V (B) 100 V (C) 130 V (D) 50 V

Tardigrade Admin · Accepted Answer

V text supply 2=(VL-VC)2+VR2 =(90 V -60 V )2+(40 V )2=(30 V )2+(40 V )2 ⇒ V=50 V

Q. An inductor, a capacitor and a resistor are connected in series to an $A C$ supply. When measured with an $A C$ voltmeter, the potential difference across the inductor, capacitor and resistor are respectively $90 V, 60 V$ and $40 V .$ Then the supply voltage is

190 V

100 V

130 V

50 V

$V_{supply}^{2} = (V_{L} - V_{C})^{2} + V_{R}^{2}$
$= (90 V - 60 V)^{2} + (40 V)^{2} = (30 V)^{2} + (40 V)^{2}$
$\Rightarrow V = 50 V$

Q. An inductor, a capacitor and a resistor are connected in series to an AC supply. When measured with an AC voltmeter, the potential difference across the inductor, capacitor and resistor are respectively 90V,60V and 40V. Then the supply voltage is