An inductor 20 mH, a capacitor 100 μ F and a resistor 50 Ω are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is

Question

An inductor 20 mH, a capacitor 100 μ F and a resistor 50 Ω are connected in series across a source of emf, V = 10 sin 314 t. The power loss in the circuit is (A) 1.13 W (B) 0.79 W (C) 2.74 W (D) 0.43 W

Tardigrade Admin · Accepted Answer

Pav = ((VRMS/Z))2 R Z = √R2 + (ω L - (1/ω C))2 = 56 Ω ∴ Pav = ((10/(√2)56))2 ×50 = 0.79 W

Q. An inductor $20 m H$ , a capacitor $100 μ F$ and a resistor $50 Ω$ are connected in series across a source of emf, $V = 10 s in 314 t$ . The power loss in the circuit is

1.13 W

0.79 W

2.74 W

0.43 W

$P_{a v} = (\frac{V _{RMS}}{Z})^{2} R$
$Z = R^{2} + (ω L - \frac{1}{ω C})^{2} = 56 Ω$
$∴ P_{a v} = (\frac{10}{( 2 ) 56})^{2} \times 50 = 0.79 W$

Q. An inductor 20mH, a capacitor 100μF and a resistor 50Ω are connected in series across a source of emf, V=10sin314t. The power loss in the circuit is