Question

An increase in pressure required to decrease the $200$ litres volume of a liquid by $0.004\%$ in pipa is
(Bulk modulus of the liquid $=2100Mpa$ )

• A. 188 kPa
• B. 8.4 kPa
• C. 18.8 kPa
• D. 84 kPa

Answer 1

Answer: (D)

Bulk modulus is given by
$K=\frac{\Delta P}{\Delta V/V}$
Given : $K=2100\times 10^{6}PaV=200$ lit.
$\Delta V=200\times \frac{0.004}{100}=0.008$ lit
Putting the given values in eq (i)
$2100\times 10^6=\frac{\Delta P}{0.008/200}$
so, $\Delta P=\frac{2100\times 10^6\times 0.008}{200}$
$=84000Pa=84\times 10^3$
$=84kPa$