An inclined plane makes an angle 30° with the horizontal. A groove (OA) of length = 5 m cut in the plane makes an angle 30° with OX. A short smooth cylinder is free to slide down the influence of gravity. The time taken by the cylinder to reach from A to O is (g = 10 m/s2)

Question

An inclined plane makes an angle 30° with the horizontal. A groove (OA) of length = 5 m cut in the plane makes an angle 30° with OX. A short smooth cylinder is free to slide down the influence of gravity. The time taken by the cylinder to reach from A to O is (g = 10 m/s2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/e8efc7fbda39b1f197c494dc34e41ffe-.png" /> (A) 4 s (B) 2 s (C) 3 s (D) 1 s

Tardigrade Admin · Accepted Answer

Acceleration of cylinder down the plane is a=(g sin 30°)(sin 30°) =10 ((1/2))((1/2)) =2.5 m/s2 time taken: t=√(2s/a) =√(2×5/2.5)=2 s

$4 s$

$2 s$

$3 s$

$1 s$

Acceleration of cylinder down the plane is

$a = (g s in 3 0^{\circ}) (s in 3 0^{\circ})$

$= 10 (\frac{1}{2}) (\frac{1}{2})$

$= 2.5 m / s^{2}$

time taken: $t = \frac{2 s}{a}$

$= \frac{2 \times 5}{2.5} = 2 s$

Q. An inclined plane makes an angle 30∘ with the horizontal. A groove (OA) of length =5m cut in the plane makes an angle 30∘ with OX. A short smooth cylinder is free to slide down the influence of gravity. The time taken by the cylinder to reach from A to O is (g=10m/s2)

4s

2s

3s

1s

Acceleration of cylinder down the plane is a=(gsin30∘)(sin30∘) =10(21​)(21​) =2.5m/s2 time taken: t=a2s​​ =2.52×5​​=2s

$4 s$

$2 s$

$3 s$

$1 s$

Acceleration of cylinder down the plane is

$a = (g s in 3 0^{\circ}) (s in 3 0^{\circ})$

$= 10 (\frac{1}{2}) (\frac{1}{2})$

$= 2.5 m / s^{2}$

time taken: $t = \frac{2 s}{a}$

$= \frac{2 \times 5}{2.5} = 2 s$