An ideal spring with spring constant k = 200 N/m is fixed on one end of a wall. If the spring is pulled with a force 10 N at the other end along its length, how much it will be extended?

Question

An ideal spring with spring constant k = 200 N/m is fixed on one end of a wall. If the spring is pulled with a force 10 N at the other end along its length, how much it will be extended? (A) 5 cm (B) 2m (C) 2 cm (D) 5 m

Tardigrade Admin · Accepted Answer

From Hookes law, F=-k x So, 10=200 × x ⇒ x=(10/200) =0.05 m=5 cm

Q. An ideal spring with spring constant $k = 200 N / m$ is fixed on one end of a wall. If the spring is pulled with a force $10 N$ at the other end along its length, how much it will be extended?

5 cm

2m

2 cm

5 m

From Hookes law,
$F = - k x$
So, $10 = 200 \times x$
$\Rightarrow x = \frac{10}{200}$
$= 0.05 m = 5 c m$

Q. An ideal spring with spring constant k=200N/m is fixed on one end of a wall. If the spring is pulled with a force 10N at the other end along its length, how much it will be extended?

5 cm

2m

2 cm

5 m

From Hookes law, F=−kx So, 10=200×x ⇒x=20010​ =0.05m=5cm

Q. An ideal spring with spring constant $k = 200 N / m$ is fixed on one end of a wall. If the spring is pulled with a force $10 N$ at the other end along its length, how much it will be extended?

From Hookes law,
$F = - k x$
So, $10 = 200 \times x$
$\Rightarrow x = \frac{10}{200}$
$= 0.05 m = 5 c m$