An ideal mono-atomic gas of given mass is heated at constant pressure. In this process, the fraction of supplied heat energy used for the increase of the internal energy of the gas is

Question

An ideal mono-atomic gas of given mass is heated at constant pressure. In this process, the fraction of supplied heat energy used for the increase of the internal energy of the gas is (A) 3/8 (B) 3/5 (C) 3/4 (D) 2/5

Tardigrade Admin · Accepted Answer

Fraction =(Δ U/Δ Q)=(CV/Cp) For monoatomic gas (Cp/CV)=&gamma;=(5/3) So, (CV/Cp)=(1/&gamma;)=(3/5)

Q. An ideal mono-atomic gas of given mass is heated at constant pressure. In this process, the fraction of supplied heat energy used for the increase of the internal energy of the gas is

3/8

3/5

3/4

2/5

Fraction $= \frac{Δ U}{Δ Q} = \frac{C _{V}}{C _{p}}$
For monoatomic gas $\frac{C _{p}}{C _{V}} = γ = \frac{5}{3}$
So, $\frac{C _{V}}{C _{p}} = \frac{1}{γ} = \frac{3}{5}$

Q. An ideal mono-atomic gas of given mass is heated at constant pressure. In this process, the fraction of supplied heat energy used for the increase of the internal energy of the gas is

3/8

3/5

3/4

2/5

Fraction =ΔQΔU​=Cp​CV​​ For monoatomic gas CV​Cp​​=γ=35​ So, Cp​CV​​=γ1​=53​

Fraction $= \frac{Δ U}{Δ Q} = \frac{C _{V}}{C _{p}}$
For monoatomic gas $\frac{C _{p}}{C _{V}} = γ = \frac{5}{3}$
So, $\frac{C _{V}}{C _{p}} = \frac{1}{γ} = \frac{3}{5}$