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Question
Physics
An ideal heat engine exhausting heat at 77° C is to have 30 % efficiency. It must take heat at
Q. An ideal heat engine exhausting heat at
7
7
∘
C
is to have
30%
efficiency. It must take heat at
2299
225
Punjab PMET
Punjab PMET 2005
Thermodynamics
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A
12
7
∘
C
7%
B
22
7
∘
C
81%
C
32
7
∘
C
8%
D
67
3
∘
C
4%
Solution:
Given :
T
2
=
77
+
273
=
350
K
Efficiency
η
=
(
1
−
T
1
T
2
)
×
100
30
=
(
1
−
T
1
350
)
100
1
−
T
1
350
=
10
3
T
1
350
=
10
7
T
1
=
7
350
×
10
=
500
K
=
500
−
273
=
22
7
∘
C