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Tardigrade
Question
Physics
An ideal gas heat engine is operating between 227° C and 127° C. It absorbs 104 J of heat at the higher temperature. The amount of heat converted into work is
Q. An ideal gas heat engine is operating between
22
7
∘
C
and
12
7
∘
C
. It absorbs
1
0
4
J
of heat at the higher temperature. The amount of heat converted into work is
2475
181
Thermodynamics
Report Error
A
2000 J
B
4000 J
C
8000 J
D
5600 J
Solution:
η
=
1
−
(
T
2
/
T
1
)
η
=
1
−
(
227
+
273
)
(
127
+
273
)
=
1
−
500
400
=
5
1
W
=
η
Q
1
=
5
1
×
1
0
4
=
2000
J