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Q. An ideal gas heat engine is operating between $227^{\circ} C$ and $127^{\circ} C$. It absorbs $10^{4} J$ of heat at the higher temperature. The amount of heat converted into work is

Thermodynamics

Solution:

$η =1- (T_2/T_1)$
$η =1 - \frac{(127 + 273)}{(227 + 273)} $
$= 1 - \frac{400}{500} = \frac{1}{5}$
$W = ηQ_1 =\frac{1}{5} \times 10^4 = 2000\, J$