Question

An ideal gas has volume $V_0$ at $27{}^{\circ }C$ It is heated at constant pressure, so/ that its volume becomes $2V_0.$ Then the final temperature is

• A. 327 K
• B. $327{}^{\circ }C$
• C. $54{}^{\circ }C$
• D. 150 K

Answer 1

Answer: (B)

For an ideal gas, at constant pressure
$V\propto T$
$\therefore \frac{V_2}{V_1}=\frac{T_2}{T_1}$
$\Rightarrow T_2=\frac{V_2}{V_1}{T}_1$
Given : $V_1=V_0,V_2=2V_0$
$T_1=27^{\circ }C=300K$
$T_2=\frac{2V_0}{V_0}\times 300=600K$
$=(600-273{)}^{\circ }C=327^{\circ }C$