Question

An ideal gas has volume $V_0$ at $ 27{}^\circ C $ It is heated at constant pressure, so/ that its volume becomes $ 2V_{0}. $ Then the final temperature is

• A. 327 K
• B. $ 327{}^\circ C $
• C. $ 54{}^\circ C $
• D. 150 K

Answer 1

Answer: (B)

For an ideal gas, at constant pressure
$V \propto T $
$\therefore \frac{V_{2}}{V_{1}}=\frac{T_{2}}{T_{1}}$
$ \Rightarrow T_{2}=\frac{V_{2}}{V_{1}} T_{1}$
Given : $V_{1}=V_{0}, V_{2}=2 V_{0} $
$ T_{1}=27^{\circ} C =300 \,K $
$T_{2}= \frac{2 V_{0}}{V_{0}} \times 300=600\, K$
$=(600-273)^{\circ} C =327^{\circ} C$