An ideal gas has pressure p0 in container of volume V0 .The number of molecules of the gas is doubled without changing the temperature. What is the new value of pressure times volume?

Question

An ideal gas has pressure p0 in container of volume V0 .The number of molecules of the gas is doubled without changing the temperature. What is the new value of pressure times volume? (A) (p0 V0/4) (B) (p0 V0/2) (C)  beginarrayll text C. p0 V0 endarray (D) D. 2 p0 V0

Tardigrade Admin · Accepted Answer

Use PV=nRT and n is doubled, rest is same

Q. An ideal gas has pressure $p_{0}$ in container of volume $V_{0}$ .The number of molecules of the gas is doubled without changing the temperature. What is the new value of pressure times volume?

$\frac{p _{0} V _{0}}{4}$

$\frac{p _{0} V _{0}}{2}$

$C. p_{0} V_{0}$

D. $2 p_{0} V_{0}$

Use $P V = n RT$ and $n$ is doubled, rest is
same

Q. An ideal gas has pressure p0​ in container of volume V0​ .The number of molecules of the gas is doubled without changing the temperature. What is the new value of pressure times volume?

4p0​V0​​

2p0​V0​​

C. p0​​V0​​

D. 2p0​V0​