Question

An ideal gas has pressure $p_{0}$ in container of volume $V_{0}$ .The number of molecules of the gas is doubled without changing the temperature. What is the new value of pressure times volume?

• A. $\frac{p_{0} V_{0}}{4}$
• B. $\frac{p_{0} V_{0}}{2}$
• C. $\begin{array}{ll}\text { C. } p_0 & V_0\end{array}$
• D. D. $2 p_0 \quad V_0$

Answer 1

Answer: (D)

Use $PV=nRT$ and $n$ is doubled, rest is
same