Q.
An ideal gas has molar specific heat 5R/2 at constant pressure. If 300J of heat is given to two moles of gas at constant pressure, the change in temperature is
The heat required at constant pressure Q=nCpΔT ∴ Change in temperature ΔT=nCpQ
Here: Q=300J,n=2 mole Cp=25R R, the gas constant =8.31Jmol−1K−1 ∴ΔT=2×25×8.31300 =5×8.31300=7.22∘C