An ideal diode is connected in a circuit with resistance R=50 Ω and V=10 V . If an AC input signal shown in the figure is given to the circuit, then the maximum and minimum value of output voltage (without load) is

Question

An ideal diode is connected in a circuit with resistance R=50 Ω and V=10 V . If an AC input signal shown in the figure is given to the circuit, then the maximum and minimum value of output voltage (without load) is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-arqkcxo94uvavh52.jpg" /> (A) 10 V,-15 V (B) 10 V,-25 V (C) 25 V,-25 V (D) 25 V,-15 V

Tardigrade Admin · Accepted Answer

For the positive half cycle, the diode is in reverse bias. Due to this there will be no current in the resistor, hence the output voltage

V_{output} = 10 V

For the negative half cycle,
the potential difference across output

= - 25 V

Q. An ideal diode is connected in a circuit with resistance R=50Ω and V=10V . If an AC input signal shown in the figure is given to the circuit, then the maximum and minimum value of output voltage (without load) is

10 V,-15 V

10 V,-25 V

25 V,-25 V

25 V,-15 V

For the positive half cycle, the diode is in reverse bias. Due to this there will be no current in the resistor, hence the output voltage Voutput​=10V For the negative half cycle, the potential difference across output =−25V

Q. An ideal diode is connected in a circuit with resistance $R = 50 Ω$ and $V = 10 V$ . If an $A C$ input signal shown in the figure is given to the circuit, then the maximum and minimum value of output voltage (without load) is

For the positive half cycle, the diode is in reverse bias. Due to this there will be no current in the resistor, hence the output voltage
$V_{output} = 10 V$
For the negative half cycle,
the potential difference across output $= - 25 V$