Question

An extended object is placed at point $O,10cm$ in front of a convex lens $L_1$ and a concave lens $L_2$ is placed $10cm$ behind it, as shown in the figure. The radii of curvature of all the curved surfaces in both the lenses are $20cm$. The refractive index of both the lenses is $1.5$. The total magnification of this lens system is

• A. 0.4
• B. 0.8
• C. 1.3
• D. 1.6

Answer 1

Answer: (B)

$\frac{1}{f_1}=(1.5-1)\left(\frac{1}{20}+\frac{1}{20}\right)=\frac{1}{20}$
$\frac{1}{f_2}=(1.5-1)\left(-\frac{1}{20}-\frac{1}{20}\right)=-\frac{1}{20}$
So, $\frac{1}{v}-\frac{1}{-10}=\frac{1}{20}$
So, $v=-20cm$
and $\frac{1}{v^{\prime }}-\frac{1}{-30}=\frac{1}{-20}$
So, $v^{\prime }=-12cm$
So total magnification $=\left(\frac{-20}{-10}\right)\left(\frac{-12}{-30}\right)=0.8$