An excess of AgNO3 solution is added to 100mL of a 0.2M solution of dichloridotetraaquachromium (.III.) chloride. The number of millimoles of AgCl precipitated would be .

Question

An excess of AgNO3 solution is added to 100mL of a 0.2M solution of dichloridotetraaquachromium (.III.) chloride. The number of millimoles of AgCl precipitated would be . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

100mL of 0.2M solution means 0.02 mole of complex (∵ (100/1000) × 0 . 2 = 0 . 02) [ Cr ( H 2 O )4 Cl 2] Cl has one ionizable Cl - ∴ 0.02 moles of the complex precipitates the same amount of AgCl . ∴ Millimoles of AgCl precipitated =20

Q. An excess of $A g N O_{3}$ solution is added to $100 m L$ of a $0.2 M$ solution of dichloridotetraaquachromium $(III)$ chloride. The number of millimoles of $A g Cl$ precipitated would be _______.

$100 m L$ of $0.2 M$ solution means $0.02$ mole of complex $(∵ \frac{100}{1000} \times 0.2 = 0.02)$
$[C r (H_{2} O)_{4} C l_{2}] Cl$ has one ionizable $C l^{-}$
$∴ 0.02$ moles of the complex precipitates the same amount of $A g Cl$ .
$∴$ Millimoles of $A g Cl$ precipitated $= 20$

Q. An excess of AgNO3​ solution is added to 100mL of a 0.2M solution of dichloridotetraaquachromium (III) chloride. The number of millimoles of AgCl precipitated would be _______.

100mL of 0.2M solution means 0.02 mole of complex (∵1000100​×0.2=0.02) [Cr(H2​O)4​Cl2​]Cl has one ionizable Cl− ∴0.02 moles of the complex precipitates the same amount of AgCl . ∴ Millimoles of AgCl precipitated =20

Q. An excess of $A g N O_{3}$ solution is added to $100 m L$ of a $0.2 M$ solution of dichloridotetraaquachromium $(III)$ chloride. The number of millimoles of $A g Cl$ precipitated would be _______.

$100 m L$ of $0.2 M$ solution means $0.02$ mole of complex $(∵ \frac{100}{1000} \times 0.2 = 0.02)$
$[C r (H_{2} O)_{4} C l_{2}] Cl$ has one ionizable $C l^{-}$
$∴ 0.02$ moles of the complex precipitates the same amount of $A g Cl$ .
$∴$ Millimoles of $A g Cl$ precipitated $= 20$