An excess of AgNO 3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be:

Question

An excess of AgNO 3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be: (A) 0.002 (B) 0.001 (C) 0.003 (D) 0.01

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/591ab4c08aa1ced3fccc0d754ef9fb5f-.png" /> ∴ mole of AgCl =1 × 10-3=0.001

Q. An excess of $A g N O_{3}$ is added to $100 m L$ of a $0.01 M$ solution of dichlorotetraaquachromium (III) chloride. The number of moles of $A g Cl$ precipitated would be:

0.002

0.001

0.003

0.01

$∴$ mole of $A g Cl = 1 \times 1 0^{- 3} = 0.001$

Q. An excess of AgNO3​ is added to 100mL of a 0.01M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be: