An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of engine is 60 %. If g=10 ms -2, the power of the engine is

Question

An engine pumps up 100 kg of water through a height of 10 m in 5 s. Given that the efficiency of engine is 60 %. If g=10 ms -2, the power of the engine is (A) 3.3 kW (B) 0.33 kW (C) 0.033 kW (D) 33 kW

Tardigrade Admin · Accepted Answer

Power is the rate at which a force does work.
Efficiency of engine,

η = 60%

Thus, power

= \frac{work / times}{η} = \frac{100}{60} \times \frac{m g h}{t}

Given,

m = 100 k g, h = 10 m, t = 5 s

and

g = 10 m s^{- 2} .

Hence, power

= \frac{100}{60} \times \frac{100 \times 10 \times 10}{5}

= 3.3 \times 1 0^{3} W

= 3.3 kW

Q. An engine pumps up 100kg of water through a height of 10m in 5s. Given that the efficiency of engine is 60%. If g=10ms−2, the power of the engine is

3.3 kW

0.33 kW

0.033 kW

33 kW

Power is the rate at which a force does work. Efficiency of engine, η=60% Thus, power =η work / times ​=60100​×tmgh​ Given, m=100kg,h=10m,t=5s and g=10ms−2. Hence, power =60100​×5100×10×10​ =3.3×103W =3.3kW

Q. An engine pumps up $100 k g$ of water through a height of $10 m$ in $5 s$ . Given that the efficiency of engine is $60%$ . If $g = 10 m s^{- 2}$ , the power of the engine is