An engine develops 10 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m? (Take g = 10 m s-2)

Question

An engine develops 10 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m? (Take g = 10 m s-2) (A) 4 s (B) 5 s (C) 8 s (D) 10 s

Tardigrade Admin · Accepted Answer

Power = ( textWork/ textTime) P = (mgh/t) or t= (mgh/P) Substituting the given values, we get t=( 200× 10× 40/10× 103) = 8 s

Q. An engine develops $10 kW$ of power. How much time will it take to lift a mass of $200 k g$ to a height of $40 m$ ?
(Take $g = 10 m s^{- 2}$ )

$4 s$

$5 s$

$8 s$

$10 s$

$P o w er = \frac{Work}{Time}$
$P = \frac{m g h}{t}$ or $t = \frac{m g h}{P}$
Substituting the given values, we get
$t = \frac{200 \times 10 \times 40}{10 \times 1 0 ^{3}} = 8 s$

Q. An engine develops 10kW of power. How much time will it take to lift a mass of 200kg to a height of 40m? (Take g=10ms−2)

4s

5s

8s

10s