An energy of 24.6 eV is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is

Question

An energy of 24.6 eV is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is (A) 38.2 eV (B) 49.2 eV (C) 51.8 eV (D) 79 eV

Tardigrade Admin · Accepted Answer

Required energy =I . E1+I . E2 =24.6 eV after removal of 1 text st e - He +form ( H-like), hence Bohr's model applicable. I.E2=I . EH × Z2 =13.6 × 4=54.4 eV So total energy required =24.6+54.4=79 eV

Q. An energy of $24.6 e V$ is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is

38.2 eV

49.2 eV

51.8 eV

79 eV

Required energy $= I . E_{1} + I . E_{2}$ $= 24.6 e V$
after removal of $1^{st} e^{-} H e^{+}$ form ( $H$ -like), hence Bohr's model applicable.
$I . E_{2} = I . E_{H} \times Z^{2}$
$= 13.6 \times 4 = 54.4 e V$
So total energy required $= 24.6 + 54.4 = 79 e V$

Q. An energy of 24.6eV is required to remove one of the electrons from a helium atom. The energy required to remove both electrons from helium atoms is