Question

An energy of $13.6eV$ is equal to

• A. $0.518\times 10^{-25}kcal$
• B. $6.04\times 10^{-25}kWh$
• C. $2.17\times 10^{-10}J$
• D. $2.17\times 10^{-15}kN-m$

Answer 1

Answer: (B)

$E=13.6eV$
$=13.6\times 1.6\times 10^{-19}J$ (or W-s)
$=21.76\times 10^{-19}W-s$
$=\frac{21.76\times 10^{-19}}{1000\times 60\times 60}kW-h$
$=6.04\times 10^{-25}kW-h$