An elevator starts going up with an acceleration 2 m/s2. If radius of the wheel attached to the elevator is 0.1 m, then find out number of revolutions in 10 s.

Question

An elevator starts going up with an acceleration 2 m/s2. If radius of the wheel attached to the elevator is 0.1 m, then find out number of revolutions in 10 s. (A) 160 (B) 170 (C) 180 (D) 190

Tardigrade Admin · Accepted Answer

θ=2π n=(1/2)(α)t2 n=(1/2)((a/r)) (t2/2π), Here, a=2 m/s2, r=0.1 m, t=10 s, n=? ∴ n=(1/2)((2/0.1)) (102/6.28)≈160

Q. An elevator starts going up with an acceleration 2 m/s². If radius of the wheel attached to the elevator is 0.1 m, then find out number of revolutions in 10 s.

160

170

180

190

$θ = 2 πn = \frac{1}{2} (α) t^{2}$
$n = \frac{1}{2} (\frac{a}{r}) \frac{t ^{2}}{2 π},$
Here, $a = 2 m / s^{2}, r = 0.1 m, t = 10 s, n = ?$
$∴ n = \frac{1}{2} (\frac{2}{0.1}) \frac{1 0 ^{2}}{6.28} \approx 160$

Q. An elevator starts going up with an acceleration 2 m/s2. If radius of the wheel attached to the elevator is 0.1 m, then find out number of revolutions in 10 s.

160

170

180

190

θ=2πn=21​(α)t2 n=21​(ra​)2πt2​, Here, a=2m/s2,r=0.1m,t=10s,n=? ∴n=21​(0.12​)6.28102​≈160

Q. An elevator starts going up with an acceleration 2 m/s². If radius of the wheel attached to the elevator is 0.1 m, then find out number of revolutions in 10 s.

$θ = 2 πn = \frac{1}{2} (α) t^{2}$
$n = \frac{1}{2} (\frac{a}{r}) \frac{t ^{2}}{2 π},$
Here, $a = 2 m / s^{2}, r = 0.1 m, t = 10 s, n = ?$
$∴ n = \frac{1}{2} (\frac{2}{0.1}) \frac{1 0 ^{2}}{6.28} \approx 160$