Q.
An elevator of mass 500kg is ascending upwards with a constant acceleration a=2m/s2. What is the work done by the tension in the elevator cable during its climb by 12m ? ( Take g=10m/s2)
Mass of elevator, m=500kg
Acceleration of elevator, a=2ms−2 (upward)
When elevator is going upward,
then tension in the elevator cable, T=m(g+a)=500(10+2)=6000N ∴ Work done by the tension force in the cable, W=T×s=6000×12 [∵ given s=12m] =72000J=72kJ