An elevator is moving up with an acceleration (g/5) . The apparent weight of a 60kg man standing in the lift is [Take g=10ms- 2 ]:

Question

An elevator is moving up with an acceleration (g/5) . The apparent weight of a 60kg man standing in the lift is [Take g=10ms- 2 ]: (A) 480N (B) 720N (C) 600N (D) 1000N

Tardigrade Admin · Accepted Answer

Apparent weight =mg+ma =60( g + (m/5))=(6 g/5)× 60=72g =72× 10N=720N

Q. An elevator is moving up with an acceleration $\frac{g}{5}$ . The apparent weight of a $60 k g$ man standing in the lift is [Take $g = 10 m s^{- 2}$ ]:

$480 N$

$720 N$

$600 N$

$1000 N$

Apparent weight $= m g + ma$
$= 60 (g + \frac{m}{5}) = \frac{6 g}{5} \times 60 = 72 g$
$= 72 \times 10 N = 720 N$

Q. An elevator is moving up with an acceleration 5g​ . The apparent weight of a 60kg man standing in the lift is [Take g=10ms−2 ]:

480N

720N

600N

1000N