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  4. An elevator is moving up with an acceleration (g/5) . The apparent weight of a 60kg man standing in the lift is [Take g=10ms- 2 ]:

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Q. An elevator is moving up with an acceleration $\frac{g}{5}$ . The apparent weight of a $60kg$ man standing in the lift is [Take $g=10ms^{- 2}$ ]:

NTA AbhyasNTA Abhyas 2020

Solution:

Apparent weight $=mg+ma$
$=60\left( g + \frac{m}{5}\right)=\frac{6 g}{5}\times 60=72g$
$=72\times 10N=720N$