An elevator cabin has a mass of 900 kg (excluding man's mass) A man is standing in it. When the cabin is pulled upwards with a force of 7000 N, the man feels a normal force of 700 N on his feet. How much normal force (in N ) will he feel if we pull the cabin upward with a force of 10,000 N.

Question

An elevator cabin has a mass of 900 kg (excluding man's mass) A man is standing in it. When the cabin is pulled upwards with a force of 7000 N, the man feels a normal force of 700 N on his feet. How much normal force (in N ) will he feel if we pull the cabin upward with a force of 10,000 N. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/093524ab95d48e3c822b7103c59f27fb-.png" /> -2700=900 a a =-3 m / s 2 700- mg = m ×-3 700=7 × m ⇒ m =100 kg 10000-1000 g =1000 a ⇒ a =0 N =100 g =1000 N

Q. An elevator cabin has a mass of 900kg (excluding man's mass) A man is standing in it. When the cabin is pulled upwards with a force of 7000N, the man feels a normal force of 700N on his feet. How much normal force (in N ) will he feel if we pull the cabin upward with a force of 10,000N.

−2700=900a a=−3m/s2 700−mg=m×−3 700=7×m⇒m=100kg 10000−1000g=1000a ⇒a=0 N=100g=1000N

$- 2700 = 900 a$
$a = - 3 m / s^{2}$
$700 - m g = m \times - 3$
$700 = 7 \times m \Rightarrow m = 100 k g$
$10000 - 1000 g = 1000 a$
$\Rightarrow a = 0$
$N = 100 g = 1000 N$