Question

An element has magnetic moment $4\sqrt{3}$ B.M, has set of quantum numbers for two consequitive unpaired higer energy electron as $n=3,\ell =2,m=-1,s=+\frac{1}{2}$ and $n=3,\ell =2,m=-2,s=+\frac{1}{2}$, What are the possible quantum number of next highter energy unpaired electron.

• A. $n=3,\ell =2,m=0,s=+\frac{1}{2}$
• B. $n=3,\ell =2,m=+1,s=+\frac{1}{2}$
• C. $n=4,\ell =0,m=0,s=+\frac{1}{2}$
• D. $n=3,\ell =2,m=+2,s=+\frac{1}{2}$

Answer 1

Answer: (A), (B), (D)

See the magnetic moment it contain six unpaired electrons. out off six for two electron, quantum numbers written and others are written in four options.