An element forms an oxide, in which the oxygen is 20 % of the oxide by weight, the equivalent weight of the given element will be

Question

An element forms an oxide, in which the oxygen is 20 % of the oxide by weight, the equivalent weight of the given element will be (A) 32 (B) 40 (C) 60 (D) 128

Tardigrade Admin · Accepted Answer

In metal oxide 0 = 20 % M = 80 % If 20 g of oxygen associates with 80 g, then 8 g of oxygen associates with metal (80/20) × 8 = 32 g of metal ∴ Eq. wt. of metal = 32 g

Q. An element forms an oxide, in which the oxygen is $20%$ of the oxide by weight, the equivalent weight of the given element will be

32

40

60

128

In metal oxide
$0 = 20%$
$M = 80%$
If 20 g of oxygen associates with 80 g, then 8 g of oxygen associates with metal $\frac{80}{20} \times 8 = 32$ g of metal
$∴$ Eq. wt. of metal $= 32$ g

Q. An element forms an oxide, in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be

32

40

60

128

In metal oxide 0=20% M=80% If 20 g of oxygen associates with 80 g, then 8 g of oxygen associates with metal 2080​×8=32g of metal ∴ Eq. wt. of metal =32 g

Q. An element forms an oxide, in which the oxygen is $20%$ of the oxide by weight, the equivalent weight of the given element will be

In metal oxide
$0 = 20%$
$M = 80%$
If 20 g of oxygen associates with 80 g, then 8 g of oxygen associates with metal $\frac{80}{20} \times 8 = 32$ g of metal
$∴$ Eq. wt. of metal $= 32$ g