An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1. A proton of mass mp, also, initially at rest, takes time t 2 to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t 2 / t 1 is nearly equal to :-

Question

An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1. A proton of mass mp, also, initially at rest, takes time t 2 to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t 2 / t 1 is nearly equal to :- (A) 1 (B) ( m p / m e )1 / 2 (C) ( m e / m p )1 / 2 (D) 1836

Tardigrade Admin · Accepted Answer

S =(1/2) ( eE / m e ) t 12 =(1/2) ( eE / m p ) t 22 m e t 22= m p t 12

1

$(m_{p} / m_{e})^{1/2}$

$(m_{e} / m_{p})^{1/2}$

1836

$S = \frac{1}{2} \frac{e E}{m _{e}} t_{1}^{2}$
$= \frac{1}{2} \frac{e E}{m _{p}} t_{2}^{2}$
$m_{e} t_{2}^{2} = m_{p} t_{1}^{2}$

1

(mp​/me​)1/2

(me​/mp​)1/2

1836

S=21​me​eE​t12​ =21​mp​eE​t22​ me​t22​=mp​t12​

$(m_{p} / m_{e})^{1/2}$

$(m_{e} / m_{p})^{1/2}$

$S = \frac{1}{2} \frac{e E}{m _{e}} t_{1}^{2}$
$= \frac{1}{2} \frac{e E}{m _{p}} t_{2}^{2}$
$m_{e} t_{2}^{2} = m_{p} t_{1}^{2}$