An electron of mass m and charge e is accelerated from rest through a potential difference V. The kinetic energy of the electron is:

Question

An electron of mass m and charge e is accelerated from rest through a potential difference V. The kinetic energy of the electron is: (A) MeV (B) eV (C) (1/2) e V2 (D) (1/2) m e V2

Tardigrade Admin · Accepted Answer

In the given conditions, the electron will acquire a velocity V v=√(2 e V/m) K.E. =(1/2) m v2 =(1/2) m ⋅ (2 eV /m)=e V

Q. An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ . The kinetic energy of the electron is:

$M e V$

$e V$

$\frac{1}{2} e V^{2}$

$\frac{1}{2} m e V^{2}$

In the given conditions, the electron will acquire a velocity $V$

$v = \frac{2 e V}{m}$

$K . E . = \frac{1}{2} m v^{2}$

$= \frac{1}{2} m \cdot \frac{2 e V}{m} = e V$

Q. An electron of mass m and charge e is accelerated from rest through a potential difference V. The kinetic energy of the electron is:

MeV

eV

21​eV2

21​meV2