An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to

Question

An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to (A) √B/v (B) B/v (C) √v/B (D) v/B

Tardigrade Admin · Accepted Answer

The magnetic field produce by moving electron
in circular path

B = \frac{μ _{0} i}{2 r}

Where

i = \frac{q}{t} = \frac{q}{2 π r} \times v

∴ = \frac{μ _{0} q v}{4 π r ^{2}}

\Rightarrow B = v / B

Q. An electron moves in a circular orbit with a uniform speed $v$ . It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

$B / v$

$B / v$

$v / B$

$v / B$

The magnetic field produce by moving electron
in circular path $B = \frac{μ _{0} i}{2 r}$

Where $i = \frac{q}{t} = \frac{q}{2 π r} \times v$
$∴ = \frac{μ _{0} q v}{4 π r ^{2}}$
$\Rightarrow B = v / B$

Q. An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to

B/v​

B/v

v/B​

v/B

The magnetic field produce by moving electron in circular path B=2rμ0​i​ Where i=tq​=2πrq​×v ∴=4πr2μ0​qv​ ⇒B=v/B​

Q. An electron moves in a circular orbit with a uniform speed $v$ . It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

$B / v$

$B / v$

$v / B$

$v / B$

The magnetic field produce by moving electron
in circular path $B = \frac{μ _{0} i}{2 r}$

Where $i = \frac{q}{t} = \frac{q}{2 π r} \times v$
$∴ = \frac{μ _{0} q v}{4 π r ^{2}}$
$\Rightarrow B = v / B$