An electron is rotating around an infinite positive linear charge in a circle of radius 0.1 m, if the linear charge density is 1 μ C / m, then the velocity of electron in m / s will be

Question

An electron is rotating around an infinite positive linear charge in a circle of radius 0.1 m, if the linear charge density is 1 μ C / m, then the velocity of electron in m / s will be (A) 0.562 × 107 (B) 5.62 × 107 (C) 562 × 107 (D) 0.0562 × 107

Tardigrade Admin · Accepted Answer

(m v2/r)=q E (m v2/r)=e ⋅ (λ/2 π ε0 r) v=5.62 × 107 m / s

Q. An electron is rotating around an infinite positive linear charge in a circle of radius $0.1 m$ , if the linear charge density is $1 μ C / m$ , then the velocity of electron in $m / s$ will be

$0.562 \times 1 0^{7}$

$5.62 \times 1 0^{7}$

$562 \times 1 0^{7}$

$0.0562 \times 1 0^{7}$

$\frac{m v ^{2}}{r} = qE$
$\frac{m v ^{2}}{r} = e \cdot \frac{λ}{2 π ε _{0} r}$
$v = 5.62 \times 1 0^{7} m / s$

Q. An electron is rotating around an infinite positive linear charge in a circle of radius 0.1m, if the linear charge density is 1μC/m, then the velocity of electron in m/s will be

0.562×107

5.62×107

562×107

0.0562×107