An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 × 10-2 T. If the value of e / m is 1.76 × 1011 C / kg, the frequency of revolution of the electron is

Question

An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 × 10-2 T. If the value of e / m is 1.76 × 1011 C / kg, the frequency of revolution of the electron is (A) 1 GHz (B) 100 MHz (C) 62.8 MHz (D) 6.28 MHz

Tardigrade Admin · Accepted Answer

f = (qB/2π m) = ((q/m)) . (B/2π) = (1.76 ×1011 ×3.57 ×10-2/2 ×3.14) = 1 ×109 Hz = 1 GHz

Q. An electron is moving in a circular path under the influence of a transverse magnetic field of $3.57 \times 1 0^{- 2} T$ . If the value of $e / m$ is $1.76 \times 1 0^{11} C / k g$ , the frequency of revolution of the electron is

1 GHz

100 MHz

62.8 MHz

6.28 MHz

$f = \frac{qB}{2 πm}$
$= (\frac{q}{m}) . \frac{B}{2 π}$
$= \frac{1.76 \times 1 0 ^{11} \times 3.57 \times 1 0 ^{- 2}}{2 \times 3.14}$
$= 1 \times 1 0^{9} Hz$
$= 1 G Hz$

Q. An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57×10−2T. If the value of e/m is 1.76×1011C/kg, the frequency of revolution of the electron is