An electron in H -atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom H ( g ) longrightarrow H +( g )+ e - ; Δ H =13.6 eV atom -1 Thus, kinetic energy given to the emitted electron is

Question

An electron in H -atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom H ( g ) longrightarrow H +( g )+ e - ; Δ H =13.6 eV atom -1 Thus, kinetic energy given to the emitted electron is (A) -21.4 eV (B) 20.4 eV (C) 35 eV (D) 21.4 eV

Tardigrade Admin · Accepted Answer

underset**E 1= Energy of H -atom in the ground state =13.6 eV Energy absorbed =(13.6 × 1.5)=20.4 eV E 2= Energy of the excited state =13.6+20.4=34.0 eV Δ E = KE =( E 2- E 1) =34.0-13.6=20.4 eV

Q. An electron in $H$ -atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom
$H (g) ⟶ H^{+} (g) + e^{-}; Δ H = 13.6 e Va t o m^{- 1}$
Thus, kinetic energy given to the emitted electron is

-21.4 eV

20.4 eV

35 eV

21.4 eV

$** E_{1} =$ Energy of $H$ -atom in the ground state $= 13.6 e V$

Energy absorbed $= (13.6 \times 1.5) = 20.4 e V$

$E_{2} =$ Energy of the excited state

$= 13.6 + 20.4 = 34.0 e V$

$Δ E = K E = (E_{2} - E_{1})$

$= 34.0 - 13.6 = 20.4 e V$

Q. An electron in H -atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom H(g)⟶H+(g)+e−;ΔH=13.6eVatom−1 Thus, kinetic energy given to the emitted electron is